Frequency Game | GeeksForGeeks Problem of the Day | 31May

 Given an array A of size N. The elements of the array consist of positive integers. You have to find the largest element with minimum frequency.

Example 1:

Input: 
5
2 2 5 50 1
Output:
50
Explanation :
All elements are having frequency 1 except 2.
50 is the maximum element with minimum frequency.

Example 2:

Input:
4
3 3 5 5
Output:
5
Explanation:
Both 3 and 5 have the same frequency, so 5 should be returned.

User Task:
Your task is to complete the provided function LargButMinFreq(A, n) which accepts array A and n. Hence you have to return the largest element with minimum frequency.

Expected Time Complexity: O(N)
Expected Space Complexity: O(N)

Constraints:
1 <= N <= 105
1 <= A[i] <= 106


SOLUTION(in C++) -


//{ Driver Code Starts

// Initial Template for C++


#include <bits/stdc++.h>

using namespace std;



// } Driver Code Ends

// User function Template for C++


class Solution{

public:

    int LargButMinFreq(int a[], int n) {

        // code here

        map<int, int> m;

        for(int i =0;i<n;i++){

            m[a[i]]++;

        }

        int mini = INT_MAX;

        for(auto i : m){

            if(i.second<mini){

                mini = i.second;

            }

        }

        int maxi = INT_MIN;

        for(auto i:m){

            if(i.second == mini && i.first > maxi){

                maxi = i.first;

            }

        }

        return maxi;

    }

};


//{ Driver Code Starts.


int main() {

    int t;

    cin >> t;

    // Iterating over testcases

    while (t--) {

        int n;

        cin >> n;


        int arr[n];


        for (int i = 0; i < n; i++) cin >> arr[i];

        Solution ob;


        cout << ob.LargButMinFreq(arr, n) << endl;

    }

}

// } Driver Code Ends

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